Ecological Bin Packing is problem 102 in the UVa Online Judge. Even though I include the problem description in this post, I encourage you to visit the UVa Online Judge because there you will be able to submit your solution to get it judged.
Recycling glass requires that the glass be separated by color into one of three categories: brown glass, green glass, and clear glass. In this problem you will be given three recycling bins, each containing a specified number of brown, green and clear bottles. In order to be recycled, the bottles will need to be moved so that each bin contains bottles of only one color.
The problem is to minimize the number of bottles that are moved. You may assume that the only problem is to minimize the number of movements between boxes.
For the purposes of this problem, each bin has infinite capacity and the only constraint is moving the bottles so that each bin contains bottles of a single color. The total number of bottles will never exceed 2^31.
The input consists of a series of lines with each line containing 9
integers. The first three integers on a line represent the number of
brown, green, and clear bottles (respectively) in bin number 1, the
second three represent the number of brown, green and clear bottles
(respectively) in bin number 2, and the last three integers represent
the number of brown, green, and clear bottles (respectively) in bin
number 3. For example, the line
10 15 20 30 12 8 15 8 31
indicates that there are 20 clear bottles in bin 1, 12 green bottles
in bin 2, and 15 brown bottles in bin 3.
Integers on a line will be separated by one or more spaces. Your program should process all lines in the input file.
For each line of input there will be one line of output indicating what color bottles go in what bin to minimize the number of bottle movements. You should also print the minimum number of bottle movements.
The output should consist of a string of the three upper case characters ‘G’, ‘B’, ‘C’ (representing the colors green, brown, and clear) representing the color associated with each bin.
The first character of the string represents the color associated with the first bin, the second character of the string represents the color associated with the second bin, and the third character represents the color associated with the third bin.
The integer indicating the minimum number of bottle movements should follow the string.
If more than one order of brown, green, and clear bins yields the minimum number of movements then the alphabetically first string representing a minimal configuration should be printed.
For a given input, the answer is the first configuration in alphabetical order that corresponds to the minimum cost. Thus, for the given input we compute the cost of candidate configurations in alphabetical order and answer with the first that corresponds to the minimum cost.
Consider the following input.
The input corresponds to the following initial configuration of bottles.
The following six configurations are all the candidate configurations for any given input. We list the six configurations in alphabetical order.
For the first configuration, consider the following computation of the corresponding cost. The associated cost is the cost of moving the brown bottles to bin 0, the clear bottles to bin 1, and the green bottles to bin 2.
The cost of all configurations for the given input is the following.
The minimum cost is 30 and the first configuration with
that cost is
BCG, thus we answer
We implement the solution in the following C program.
For each line of input, we store the initial configuration in array
Moves(x, y, z) computes the cost for given configuration
y, z. Variables
min_i are respectively the minimum number of bottle
movements and the index of the corresponding configuration. Macro
SelectMin(i) selects the first solution that has the minimum cost by
min_i. The sequence of appications
Select computes the answer. The
statement prints the configuration label and the cost of the answer.
Ecological Bin Packing is a problem that asks to select the best solution out of six candidate solutions. Given that the candidate solutions are few, we consider all candidate solutions and select the best.
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